x^2/(0.1-x)=10^-4

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Solution for x^2/(0.1-x)=10^-4 equation:



x^2/(0.1-x)=10^-4
We move all terms to the left:
x^2/(0.1-x)-(10^-4)=0
Domain of the equation: (0.1-x)!=0
We move all terms containing x to the left, all other terms to the right
-x!=-0.1
x!=-0.1/-1
x!=0.1/1
x∈R
We add all the numbers together, and all the variables
x^2/(-1x+0.1)-(10^-4)=0
We add all the numbers together, and all the variables
x^2/(-1x+0.1)-0.0001=0
We multiply all the terms by the denominator
x^2-(0.0001)*(-1x+0.1)=0

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